no id - Chat started on: Nov 16, 2007 11:35:30 PM [11:35 PM] Corey Couillard has entered the room [11:35 PM] Kate Sims has entered the room [11:35 PM] This room is not anonymous. [11:35 PM] ziizoo admin: Session started on Fri Nov 16 23:36:44 EST 2007 [11:35 PM] Kate Sims: Oh good it worked! [11:35 PM] Corey Couillard: hi, not sure what happen [11:36 PM] Kate Sims: Somehow you left the room... Who knows?!? The bad news is we lost our whiteboard, but we were almost done. Did you write everything down on separate paper? [11:36 PM] Corey Couillard: yes [11:37 PM] Kate Sims: Oh good. We were just about to plug each of our points into the objective function to find the maximum. [11:37 PM] Corey Couillard: that is correct [11:37 PM] Kate Sims: Did you attempt it yet? [11:38 PM] Corey Couillard: yes [11:38 PM] Kate Sims: And which was the maximum? [11:38 PM] Corey Couillard: b=50, r=300 [11:39 PM] Kate Sims: Yes, good. [11:39 PM] Corey Couillard: do I put that on the graph [11:40 PM] Kate Sims: You can, but you don't have to as long as it's with your other work. [11:41 PM] Kate Sims: I sent you a message summarizing the steps we did. Do you have any other questions about this problem? [11:41 PM] Corey Couillard: ok, I just want to make sure that I understand this. I plugged 300 in for r because to consume all the pork and that is how I derived 50 is that correct? [11:42 PM] Corey Couillard: than I just have to plug these quanities in profit statement to determine total profit [11:42 PM] Kate Sims: No, you're actually not using all of the pork. [11:43 PM] Kate Sims: The reason we plugged in 300 is we were looking for where those two lines crossed to make the corner. The two inequalities were (1/2)R + B <=200 and R <=300, so the lines represented (1/2)R + B = 200 and R = 300. [11:43 PM] Corey Couillard: if I mfg 300 pkg wouldn't I consume 150 ib of pork [11:44 PM] Kate Sims: Hold on a second and I'll finish my other thought, then I'll get your new question. [11:44 PM] Kate Sims: So to find where the lines cross, we solved the system (1/2)R + B = 200 R = 300. This happens to be an easy system to solve, because we already know R. So we just plugged it in to get B. [11:45 PM] Kate Sims: (sorry, you're right. I was thinking of the beef, which has some left over) [11:46 PM] Kate Sims: You can't assume that you'll always use something up. A lot of these simpler book problems work out that way, but when you get more constraints and they're more complicated, that may not happen. [11:46 PM] Corey Couillard: wouldn't we consume all the beef with 50 pkgs of B and 300 pkgs of reg, that would be 200 lbs [11:47 PM] Kate Sims: Never mind. You're absoutely right. But still don't assume it'll always turn out that way. [11:48 PM] Corey Couillard: ok, I also just want to make sure that I only need one shaded area, [11:49 PM] Kate Sims: Yes, it should be one shaded area, which represents where all of the inequalities are true. [11:50 PM] Corey Couillard: that is what I thought... ok, I'll look at your note an email if I have need further clarification. Thank you....Ohh I did try to rate you but couldn't find where to do that. [11:51 PM] Kate Sims: Did you try going to "My Account" and then "Dashboard" (the first tab)? You can just send me another message if you can't find it. [11:52 PM] Corey Couillard: ok, I'll try. thank you again for being so patient with me. Have a good night [11:52 PM] Kate Sims: You're very welcome! Enjoy the rest of your weekend.